A1.50-kilogram ball is attached to the end of a 0.520-meter string and swung in a circle. the velocity of the ball is 9.78 m/s. what is the tension in the string? 74.6 n 276 n 28.2 n 3.39 n

The tension in the string is 276 N.

Explanation:

It is given that,

Mass of the ball, m = 1.5 kg

Length of the meter stick, r = 0.52 m

Velocity of the ball, v = 9.78 m/s

The tension acting in the string is balanced by the centripetal force acting on it. Its formula is given by :

or

So, the tension in the string is 276 N. Hence, this is the required solution.

newton's first law of motion

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.