How much force is needed to stretch a spring 1.2 m if the spring constant is 8.5 n/m? 7.1 n 7.3 n 9.7 n 10.2 n

The correct answer to the question is 10.2 N.

CALCULATION:

As per the question, the spring is stretched to a distance x = 1.2 m.

The spring constant of the spring is given as k = 8.5 N/m.

We are asked to calculate the force needed to stretch the spring.

When the spring is stretched, the spring produces a restoring force which opposes the stretching. It is equal and opposite to the applied deforming force.

From Hooke's law, we know that the restoring force produced on the spring is proportional to the displacement of the spring from its mean position.

Mathematically restoring force F' = -kx

Here, k is known as the force constant or spring constant. The negative sign used is due to the fact that it is opposite to the applied force.

Hence, the applied force F = kx

                                             = 8.5 N/m × 1.2 m.

                                             = 10.2 N.                         [ANS]

low freq = 100 mhz

low wavelength =101.7m

length = 3x10^8/freq