If r1 = 6 ω, r2 = 8 ω, r3 = 2 ω, ε1 = 4 v, and ε2 = 14 v, what is the current in r2?

The current in the resistor is .

Further Explanation:

There are two rectangular loops in the given circuit.

To obtain the current in both the loops we will apply Kirchhoff’s voltage law.

Given:

The resistance of first resistor is Ω.

The resistance of second resistor is Ω.

The resistance of third resistor is Ω.

The voltage of first cell is .

The voltage of second cell is .

Concept:

Kirchhoff’s law in left side loop:

Substitute Ω for , Ω for and for in above equation and simplify.

                                                                                 …… (I)

Kirchhoff’s law in right side loop:

Substitute Ω for , Ω for and for in above equation and simplify.

                                                                              …… (II)

Multiply equation (I) with

                                                                         …… (III)

Multiply equation (II) with

                                                                      …… (IV)

On adding equation (III) and equation (IV), we get

Substitute for in equation (I) and rearrange for .

Current in second resistor:

Thus, the current in the resistor is .

Learn more:

1. Threshold frequency of photoelectric surface:

2. Find the odd one out for lever:

3. Volume of gas after expansion:

Answer Details:

Grade: College

Subject: Physics

Chapter: Electricity

Keywords:

R1, R2, R3, E1, E2, current, Kirchhoff’s, voltage, loop, circuit, resistor, 6 ohm, 2 ohm, 8 ohm, 4 volt, 14 volt and law.

568.98

explanation:

its math