Aball is hit straight up with an initial speed of 28 meters per second. what is the speed of the ball 2.2 seconds after it is hit? [neglect friction.]

The velocity after 2.2sec is

Explanation:

Given information:

Initial speed of ball is

The ball is moving straight upward. So, acceleration due to gravity will act in opposite direction to the motion.

So, the acceleration of the ball will be,

It is required to find the velocity

Time

By using first equation of motion

On substituting,

Hence, the velocity after 2.2 sec is .

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it becomes positively charged by charging it

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s