A2.3-kg object traveling at 6.1 m/s collides head-on with a 3.5-kg object traveling in the opposite direction at 4.8 m/s. if the collision is perfectly elastic, what is the final speed of the 2.3-kg object?

The final speed of the 2.3-kg object is about 7.1 m/s

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

Given:

mass of object 1 = m₁ = 2.3 kg

initial velocity of object 1 = u₁ = 6.1 m/s

mass of object 2 = m₂ = 3.5 kg

initial velocity of object 2 = u₂ = -4.8 m/s

Asked:

final velocity of object 1 = v₁ = ?

Solution:

Firstly , we will use Conservation of Momentum Law as follows:

→ Equation 1

If the collision is perfectly elastic , then:

→ Equation 2

Let's solve the two Equations above:

(Equation 1) - 3.5(Equation 2) ↓

Grade: High School

Subject: Physics

Chapter: Dynamics

Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant

are you like autistic or something?

xd

well, you would divide 135 by 33 to get your answer. then that is how many seconds it would take. boardman should fly about 132 m or 4.090909090909091 seconds.