Ametal ball of mass 100 g is heated to 90°c and then cooled to 25°c. the heat lost in the process is 2.5 kj. another metal ball of mass 200 g is heated to 90°c and then cooled to 25°c. the heat lost in the process is 5.0 kj. what can be concluded from the data?

Answer: A) The balls are made of the same material.

Explanation: Specific heat = (Heat transferred) ÷ (mass × temperature difference).

Specific heat of first ball = (2.5) ÷ (100 × temperature difference)

Specific heat of second ball = (5.0) ÷ (200 × temperature difference)

Dividing the second equation by the first

Specific heat of first ball = Specific heat of second ball

So both balls are made of the same material as they have the same specific heat.

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

im sorry i dont know