The landing of a spacecraft is cushioned with the of airbags. during its landing on mars, the velocity of downward fall is 16 meters/second. immediately after the impact, the velocity is reduced to 1.2 meters/second. if the spacecraft has a mass of 11.5 × 104 kilograms, what is your estimate for the impulse if the time of impact is 0.8 seconds?

Explanation:

The impulse is equal to the product between the force (F) and the time of impact ():

However, the impulse is also equal to the change in momementum of the spacecraft:

where

is the mass of the spacecraft

is the final velocity

is the initial velocity

Substituting these numbers into the formula, we find

where the negative sign simply means that the impulse is in the opposite direction to the motion of the spacecraft (in fact, it makes it slowing down).

f=ma newton's second law 7x8=56n

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//