Jason applies a force of 4.00 newtons to a sled at an angle 62.0 degrees from the ground. what is the component of force effective in pulling the sled horizontally along the ground?

You want to draw a free body diagram of the forces on the sled in the horizontal x-direction.

If you visualize the system in an x-y coordinate plane, the force along the x-direction is the angle it makes with the x-axis multiples by the force.

The angle made with the x-axis is cosine of the angle theta.

Please see picture attached.

When a force, F, is applied to an object at an angle,θ, to compute for the horizontal and vertical components, we have the following




So, for this particular problem, given that the force applied to the sled is 4.00 N at 62⁰. Thus, the horizontal component of the force is equal to

F = 4.00(cos62⁰) = 1.88 N

Therefore, the horizontal force is 1.88 N.
1.88 N

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