Atransformer has a primary coil with 600 turns and a secondary coild of 300 turns, if the output voltage is 320 volts, what is the input voltage?

We can calculate this problem using this formula: N(p) / N(s) = V(p) / V(s).

Where in the given values are:
N(p) = 600
N(s) = 300
V(s) = 320
V(p) = ?

So;
N(p) / N(s) = V(p) / V(s)
600 / 300 = x / 320 V
192,000 = 300 x
640 = x

This will give us a value of 640 V, which is the input input voltage.