Acircuit contains a 12 volt battery and two 3 ohm bulbs in parallel.
a. what is the voltage across each branch?
b. calculate the current in each branch
c. calculate the power of each bulb
d. calculate the total current in the circuit
e. calculate the power supplied by the battery

A). Since the two bulbs are in parallel, each bulb is connected directly across the battery.  So the voltage across each bulb is 12 volts.

B). The current in each bulb is (voltage / resistance) =
                                                  (12  /    3)            = 4 Amperes.

C). The power dissipated by each bulb is (voltage x current) =
                                                               12      x    4      = 48 watts

D). The total current from the battery is (4 A per bulb) x (2 bulbs) = 8 Amperes.

E). The power supplied by the battery is (voltage x current) =
                                                               12    x    8        = 96 watts

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