An aluminum can with a mass of 12.8 g absorbs 212 j of heat. by how much does the temperature of the can increase? the specific heat capacity of aluminum is 0.91j/g * k

Heat gained or absorbed in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:

Heat = mC(T2-T1)

We calculate as follows:

212 J = 12.8 (0.91)(ΔT)

ΔT = 18.20 K

The increase in temperature is about 18.20 Kelvin.

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