Achild walks 5.0 meters north, then 4.0 meters east, and finally 2.0 meters south. what is the magnitude of the resultant displacement of the child after the entire walk

Resultant displacement of the child is 5 m.

Explanation:

It is given that, a child walks 5.0 meters north, then 4.0 meters east, and finally 2.0 meters south.

We have to find the magnitude of displacement of the child after the entire walk. The attached figure shows entire journey of the child. Displacement of an object is equal to the shortest path covered by it. Here, AM shows the net displacement. It can be calculated using Pythagoras theorem as :

Since, AB = 5 m So, OA = 3 m and BC = OM = 4 m

⇒ AM = 5 m

Hence, the resultant displacement of the child after the entire walk is 5 m.

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