Aperson drops a brick from the top of a building. the height of the building is 400 m and the mass of the brick is 2.00 kg. what will be the speed of the brick right before it touches the ground? use g=10.0 m/s^2.

This question involves the conservation of energy. There are two energy in this case, potential energy and kinetic energy. Let's divid the energy into three status. 
1. Before dropping, all potential energy 
2.dropping, potential energy transformed to kinetic energy
3. before hitting the ground, all Kinetic energy.

Recall the formula for both energy, which are U=mgh, and K=1/2mv^2

Since the energy is conserved in this case ( b/c otherwise it will say in the problem), the amount of energy at the beginning should equal to the energy at the end. Therefore we have, mgh=1/2mv^2

plug the number in and solve for velocity.

2x400x10=1/2 x 2 x v^2
v^2=8000
v=
v=40

Iread this book last year so take this with a grain of salt.gene jumps from the tree to compete with finny due to the fact that gene is always trying to do better than finny. he is put under the grasp of peer pressure due to finny almost forcing him to do this. ever since he first jumped finny kept pressuring him to jump since he thought gene enjoyed jumping.rather than uses this answer you should probably just reread chapters 3-4

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