Chang wants to build a circuit that will light up the bulb from a flashlight. which component could chang leave out and still light up the bulb? the switch the battery the wire the light bulb

As per the question Chang wants to build a circuit that will light up the bulb.

We are given four circuit elements i.e the switch,the battery,the wire,the light bulb.

Before answering, first we have to understand a switch. A switch is a circuit element which is used to on or off a circuit. So it does not affect the current to pass through the wire to light up the bulb.It can be eliminated.

We can not eliminate a battery as it creates the potential difference across the wire for which the current will flow from higher potential to lower potential. It as the source of charge.

The bulb and the wire can not be eliminated .Wire is the medium through which current will flow and the bulb is needed to light up.

Hence the correct answer is the switch.

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.

answer: the answer is a