Gabe is sitting in his boat and sees a famous building onshore which is known to be 250 meters tall. gabe sights the top of the building, and finds that the angle of elevation is 19°. about how far, in meters, is gabe from the base of the building? (disregard gabe's height from the water in your calculations.)

The distance between the gabe and the base of the building is 726.07 meters.

Explanation:

It is given that,

Gabe is sitting in his boat and sees a famous building onshore which is known to be 250 meters tall.

The angle of elevation, θ = 19°

We have to find the the distance between the gabe and the base of the building. From the attached figure, AB = height of building = 250 meters

BC = distance between the gabe and the base of the building

Using trigonometric equation as :

BC = 726.05 meters

So, the gabe is 726.05 meters away from the base of the building.

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow