Mars, which has a radius of 3.4 × 106 m and a mass of 6.4 × 1023 kg, orbits the sun, which has a mass of 2.0 × 1030 kg at a distance of 2.3 × 1011 m. which is greater, the tangential speed of mars’s rotation or revolution?

The correct answer is: Revolution (The tangential speed of Mars' revolution is greater than that of Mars' rotation).

Explanation:

Given data:

Radius-of-Mars = r =   m

Distance-between-Sun-and-Mars = d = m

Now let us first calculate the Mars' rotation:

One complete rotation of Mars = 2πr = 2π() = m

Tangential speed of Mars' rotation (by taking 24hours 37 minutes in seconds (88620s)—as Mars takes that many seconds to complete one rotation) =

Now let's calculate the Mars' revolution (around Sun):

One complete revolution of Mars around Sun = 2πd = 2π() = m

Tangential speed of Mars' revolution (by taking 687 days in seconds (59356800s)—since Mars takes 687days to complete one revolution)=

So we can see that the tagential speed of:

Revolution > Rotation

>

Hence, the correct answer is Revolution.

your answer would be fusion

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2