The electric potential energy stored in the capacitor of a defibrillator is 73 j, and the capacitance is 120 f. what is the potential difference that exists across the capacitor plates?

The relationship between electrical potential energy (PE), capacitance (C), and potential difference (V) can be expressed through the equation,

                                  V  = PE / C

V is equal to the quotient of potential energy and capacitance.

When we substitute the known values from the item,

                               V =  73 J/ 120 C

                                    V = 0.61 J/C

Thus, the voltage or potential difference is equal to 0.61 V. 

because if the tool that you are using is not balanced it there would be false mass.