Aperson standing at the edge of a seaside cliff kicks a stone over the edge with a speed of 18 m/s. the cliff is 52 m above the water's surface. with what speed did it strike the water?

Speed with which it strike the water = 36.66 m/s

Explanation:

Horizontal component of velocity = 18 m/s

We need to find vertical component of velocity.

Considering vertical motion of stone

Initial velocity, u =  0 m/s

Acceleration , a = 9.81 m/s²

Displacement, s = 52 m

We have equation of motion v² = u² + 2as

Substituting

   v² = u² + 2as

    v² = 0² + 2 x 9.81 x 52

    v = 31.94 m/s

Vertical component of velocity = 31.94 m/s

Speed with which it strike the water = 36.66 m/s

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15.3 cos 65 degrees trig