An electrical motor spins at a constant 2035 rpm. if the armature radius is 5.862 cm, what is the acceleration of the edge of the rotor?

An object that moves in a uniform circular motion would have a constant speed. However, we would not say that acceleration would be zero. The object would be accelerating due to the changes in the direction. Acceleration or this case would be the ratio of the square of its velocity an the radius of the circular motion. We would calculate as follows:

Acceleration = velocity^2 / radius
         velocity = 2035 rpm (1 min / 60 s) (5.862 cm)
         velocity = 198.8195 cm/s
Acceleration = (198.8195 cm/s)^2 / 5.862 cm = 33.92 cm/s^2

Therefore, the acceleration of the edge of the rotor would be 33.92 cm per s^2.