Atall cylinder contains 30 cm of water. oil is carefully poured into the cylinder, where it floats on top of the water, until the total liquid depth is 40 cm. part a what is the gauge pressure at the bottom of the cylinder? suppose that the density of oil is 900 kg/m3.

The total gauge pressure at the bottom of the cylinder would simply be the sum of the pressure exerted by water and pressure exerted by the oil.

The formula for calculating pressure in a column is:

P = ρ g h

Where,

P = gauge pressure

ρ = density of the liquid

g = gravitational acceleration

h = height of liquid

Adding the two pressures will give the total:

P total = (ρ g h)_water + (ρ g h)_oil

P total = (1000 kg / m^3) (9.8 m / s^2) (0.30 m) + (900 kg / m^3) (9.8 m / s^2) (0.4 - 0.30 m)

P total = 2940 Pa + 882 Pa

P total = 3,822 Pa

 The total gauge pressure at the bottom is 3,822 Pa.

where are the vectors ?