Two point charges of values +3.4 and +6.6 μc are separated by 0.10 m. what is the electrical potential at the point midway between the two point charges? (

 To solve this problem, we should remember that:

Energy = Force x Distance

Since we are talking about charges, therefore we make use of Coulumb’s law for the electrical force between the two charges:

F = k q1 q2 / d^2

Where,

k = Coulumb’s constant = 9 x 10^9 N m^2/ c^2

q = charge

d = distance between the charges

Plugging back into the energy equation:

E = (k q1 q2 / d^2) * d

E = k q1 q2 / d

Solving for E using the given values:

E = (9 x 10^9 N m^2/ c^2) (3.4 E -6 c) (6.6 E -6 c) / 0.10 m

E = 2.02 N m = 2.02 J

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2