Aman jogs at a speed of 1.1 m/s. his dog waits 1.6 s and then takes off running at a speed of 2.4 m/s to catch the man. how far will they have each traveled when the dog catches up with the man?

To solve this problem, let us first assign variables.

Let us say that,

A = man

B = dog

And the distance travelled by man and dog must be equal, therefore:

dA = dB

From the linear equations, we know that the formula for distance d is:

d = v t

where v is velocity and t is time, therefore:

vA tA = vB tB

We are given tA = tB + 1.6 s, therefore:

vA (tB + 1.6) = vB tB

1.1 (tB + 1.6) = 2.4 tB

1.1 tB + 1.76 = 2.4 tB

1.3 tB = 1.76

tB = 1.354 s

Therefore they both travelled a distance of:

dA = dB = 1.354 s * 2.4 m/s = d

d = 3.25 m

0.863333

86%

hope this

answer;

d. are made mostly of liquid

explanation;

-the general   composition and structure planets includes; they have a thick gas and liquid layer covering a small,solid core. mostly the gases are hydrogen and helium atmosphere and layers of liquid hydrogen. for instance neptune and uranus are examples of the outer planets, they have a core covered by ice and ammonia.

-neptune's atmosphere is hydrogen and helium with a bit of methane so there is no oxygen to breath and the interior is made up of frozen water and ammonia with a rock and iron core. thus, there is no liquid water or solid surface to survive.