If the meteorite was moving at 500 m/s before striking the car, what was the magnitude of its acceleration while stopping?

The solution would be like this for this specific problem:

a = v2r (formula for magnitude of acceleration)

a = 6.25 × 105 ms^-2 

Use V^2 = Vo^2 + 2a (X - Xo) 

We know that the meteorite travels at a speed of .2m, but it stops moving so V^2 has a 0 value. Also, you’re told that Vo is 500 and Xo is 0.

0 = 500^2 + 2a (.2 - 0) 
-250000 = .4a 

a = -625000. I thought that a should have been negative since it was slowing down, but it told me to change signs so a should be a = 625000 m/s^2

explanation:

as the height from which the ruler was dropped increased, the speed of the ruler at ryan's hand increased.

hello, i am papaguy.

i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!