An airplane accelerates from a velocity of 21 m/s at the constant rate of 3.0 m/s over 535 m. 2 what is its final velocity?

Initial velocity, u = 21 m/s
Acceleration, a = 3.0 m/s²
Distance traveled, s = 535 m

Let v = the final velocity.

Use the formula 
v² = u² + 2as

v² = (21 m/s)² + 2(3.0 m/s²)(535 m) =  3651 m²/s²
v = 60.42 m/s

60.42 m/s

answer and explanation;

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