Hw2-2 - show all your work, including the equation, express all answers in base units, (m, m/s, m/s2), unless stated otherwise in problem. a sprinter accelerates from rest to 10.5 m/s in 1.35 sec. what is her acceleration . . in m/s2 km/hr2 a certain drag racer can accelerate from 0 to 60.0 km/hr in 5.4 sec. what is its acceleration in m/s2? how far, in meters, will it travel during this acceleration? how much time would it take to go 0.25 km if it could accelerate at this rate the entire time? an automobile can increase its speed uniformly from 25.0 to 55.0 km/h in 30.0 seconds. a bicycle rider uniformly speeds up to 30.0 km/h from rest in 0.5 min. calculate their accelerations. a rocket rises from rest with constant acceleration to an altitude of 85.0 km, at this point it has a speed of 2.8 km/s what is the acceleration of the rocket? how long does the ascent take?

The useful equations here are derived equations for rectilinear motion at constant acceleration:

a = (v - v₀)/t
2ax = v² - v₀²
x = v₀t + 0.5at²

1.  Since it starts from rest, v₀ = 0. Then, v = 10.5 m/s and t=1.35 s
     a = (10.5 - 0)/1.35 = 7.78 m/s²
     a = 7.78 m/s²*(1 km/1000 m)*(3,600 s/ 1 h)² = 100,828.8 km/h²

2. v₀ = 0; v = 60 km/h; t=5.4 s 
    a = [60 km/h*(1000 m/1km)*(1 h/3600 s) - 0]/5.4 s = 3.09 m/s²

3. Using the acceleration and velocities in #2, we can determine the distance     by the formula: 2ax = v² - v₀²
    2(3.09 m/s²)x = [60 km/h*(1000 m/1km)*(1 h/3600 s)]² - (0 m/s)²
    Solving for x,
    x = 44.95 m

4. Using acceleration in #2 and v₀ = 0, the time would be
    x = v₀t + 0.5at²
    0.25 km * 1,000 m/1 km = (0)(t) + (0.5)(3.09 m/s²)(t²)
    Solving for t,
    t = 12.72 seconds

5. Acceleration of automobile:
   a = [(55 km/h - 25 km/h)*(1,000 m/1 km)*(1 h/3,600 s)]/30 s
   a = 0.278 m/s²

   Acceleration of bicycle:
   a = [(30 km/h - 0 km/h)*(1,000 m/1 km)*(1 h/3,600 s)]/(0.5 min * 60 s/1 min)
   a = 0.278 m/s²

6. x = 85 km or 85,000 m; v₀ = 0 m/s; v = 2,800 m/s
    2ax = v² - v₀²
    2a(85,000 m) = (2,800 m/s)² - 0²
    a = 46.12 m/s²

7. Using the data given and acceleration in #6,
   x = v₀t + 0.5at²
   85,000 m = 0*t + 0.5(46.12 m/s²)(t²)
   Solving for t,
   t = 60.71 seconds

The sample with the lowest specific heat capacity will have the greatest temperature increase. in this case, it would be platinum.

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