Rt c if you were to hit a ping pong ball of mass 0.0029 g with the same force that caused a 0.058-g tennis ball to move with an acceleration of 10 m/s2 , what would the acceleration a of the ping pong ball be? express your answer in meters per second squared.

The acceleration of the ping pong ball would be 200 m/s²

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

Given:

mass of ping pong ball = m₁ = 0.0029 g

mass of tennis ball = m₂ = 0.058 g

acceleration of tennis ball = a₂ = 10 m/s²

Asked:

acceleration of ping pong ball = a₁ = ?

Solution:

The acceleration of the ping pong ball would be 200 m/s²

Grade: High School

Subject: Physics

Chapter: Dynamics

c because the action was the roller coaster reaches bottom of hill (action) reaction would be blood tends to drain away from head

hope this !

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