Physics, 24.04.2021 14:00 solivagantjn3010

A train starting from rest accelerates at 4m/s for 5 seconds. Calculate its velocity at the end of the 5 seconds.

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Answer from: Quest

Are a.larger

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

Answer from: Quest

V=ƒλv= 320 m/shope i can i get brainliest

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Ek₀ and ep₀ are initial kinetic and potential energies respectively.ek and ep are final kinetic and potential energies respectively.energy in the system is conserved.ek₀ + ep₀ = ek + epassume student is one some ground ground, so ep₀ = 0at the apex of student's swing, ek = 0ek₀ + 0 = 0+ epek₀ = epmv₀²/2 = mghmass cancels outv₀²/2 = ghh = v₀²/(2g)h = (3.5 m/s)²/(2 * 9.81 m/s²)h = 0.62 mhe will swing 0.62 m high (relative to where he was running before)

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