Based on the graph, what can you conclude regarding the speed of Student A with student B? Distance v. Time
2.0
Student A
Distance (m)
Student B.
1.0
0.5
0
0
0.5
2.0
205
1.0
1.5
Time (s)
Student A is traveling at a speed 3X as fast as student
Student A and Student B are traveling at the same speed
Student A is traveling at a speed twice as fast as student B
Student B is traveling at a speed twice as fast as student A

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.