Find the electric force between a 7.2x10^-5c charged particle and a
3.6x10^-6c charged particle if they
are 0.75 M away from one another
is the force attractive or repulsive?

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

a=d/t

a="triangle"v/t

explanation:

a = acceleration