in the diagram, q1 = +6.60 x 10^-6 C, q2 = +3.10 x 10^-6 C, and q3 = +5.30 x 10^-6 C. find the electric potential energy of q2.

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j