if a force of 50 Newtons is applied to an object with an angle of 30 degrees above the ground, how big is the horizontal and vertical component of the force?​

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge

i already answered it by 34/s

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j