Pls pls help for brainliest pls help for brainliest:)

If an object is placed 10cm in front a double convex lens that has a focal length of 15cm, what will be the resulting distance? What type of image this?

A. 20cm; real image
B. 15cm; virtual image
C. -30cm; virtual image
D. -5cm; real image

This would be C.

Explanation:

"according to lens formula Given f = +15 , u = -10 , v= ? Hence to find v rearrange lens formula i.e = Hence v = -30 and negative sign show image is virtual." Chegg.

the answer would be   dignified - apex

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day