A pendulum that was originally erected by Foucault at the Pantheon in Paris for the Paris Exhibition in 1851 was restored in 1995. It has a 28.0 kg sphere suspended from a 67.0-m light cable. If the amplitude of the swing is 5.00 m, what is the maximum speed of the sphere

13.1 m/s

Explanation: Given that a pendulum that was originally erected by Foucault at the Pantheon in Paris for the Paris Exhibition in 1851 was restored in 1995. It has a 28.0 kg sphere suspended from a 67.0-m light cable. If the amplitude of the swing is 5.00 m, what is the maximum speed of the sphere

The formula to use is :

W = sqrt ( L/g )

Where

L = 67m

g = 9.8m/s^2

A = 5m

Substitute all the parameters into the formula

W = sqrt ( 67 / 9.8 )

W = 2.6

To get the maximum velocity, we use the below formula.

V = wA

V = 2.6 × 5

V = 13.07 m/s

Therefore the maximum speed of the sphere is 13.1 m/s approximately.

lol

explanation:

it has to be b, about 97 percent.