In a given cartesian coordinate system a particle is in the position (initial vector position) ( 9.2 , 3.1 ) meters. After 10 seconds, the particle is in the position (final vector position) ( 72.2, 77.2 ) meters. What is the magnitude of the average velocity of the particle during the given time interval, in m/s

Thus, the average velocity is 9.73 m/s.

Explanation:

The velocity is given by the rate of change of position.  

initial position, A = (9.2, 3.1) m

final position, B = (72.2, 77.2) m

time, t = 10 s

The velocity is given by

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