A hockey stick stores 4.2 J of potential energy when it is bent 3.1 cm. Treating the hockey stick as a spring, what is its spring constant

Spring constant, k = 8740.89 N/m

Explanation:

Given the following data;

Potential energy = 4.2 J

Extension, e = 3.1 cm to meters = 3.1/100 = 0.031 m

To find the spring constant;

Mathematically, the potential energy stored in a spring is given by the formula;

Where;

P.E is potential energy.

K is the spring constant.

x is the extension of the spring.

Substituting into the equation, we have;

Cross-multiplying, we have;

Spring constant, k = 8740.89 N/m

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)

d is the correct answer