Monochromatic light with wavelength 633 nn passes through a narrow slit and a patternappears on a screen 6.0 m away. The distance on the screen between the centers of thefirst minima on either side of the screen is 32 mm. How wide (in mm) is the slit

Explanation:

screen distance D = 6 m .

wavelength of light λ = 633 nm.

slit width = d .

Distance between first minima on either side is width of central maxima

= 2 x λD /d

Given

32 x 10⁻³ = 2 x λD /d

d = 2 x λD /32 x 10⁻³

= 2 x 633 x 10⁻⁹ x 6 / 32 x 10⁻³

= 237.37 x 10⁻⁶ m

= .23737 x 10⁻³ m

= .24 mm .

v=ir = 3x15 =45 v

the components of a vector are the parts of the vectors that are to each other.

b perpendicular