A projectile is launched from the ground with an initial velocity of 12ms at an angle of 30° above the horizontal. The projectile lands on a hill 7.5m away. The height at which the projectile lands is most nearly A- 1.78m
B- 3.10m
C- 5.34m
D- 6.68m
E- 12.0m

A. 1.78 m

Explanation:

Given;

initial velocity of the, u = 12 m/s

angle of projection, θ =  30°

the range of the projectile, R = 7.5 m

To obtain the height through which the projectile lands, we must calculate the maximum height reached by the projectile.

Therefore, the height is most nearly 1.78 m

if they have a finite resultant