A 150 N force, applied to a wooden crate at an angle of 30 degrees above the horizontal, causes the crate to travel at a constant velocity across a horizontal wooden floor. Please show all work for the following question A. Calculate the magnitude of the horizontal component of the 150 N force.
B. Determine the magnitude of the frictional force acting on the crate.
C. Calculate the magnitude of the normal force exerted by the floor on the crate.

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)