A 1.2-kg object moving with a speed of 8.0 m/s collides perpendicularly with a wall and emerges with a speed of 7.2 m/s in the opposite direction. If the object is in contact with the wall for 2.0 ms, what is the magnitude of the average force on the object by the wall

480N

Explanation:

Given data

M1= 1.2kg

U1= 8m/s

V1=7.2 m/s

T= 2ms= 0.002

We know that the impulse expression is

P=FT

M(U1-V1)= FT

substitute

1.2(8-7.2)= F*0.002

1.2*0.8=  F*0.002

0.96=  F*0.002

F= 0.96/0.002

F=480N

Hence the force is 480N

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