A 92-kg receiver running at 8 m/s catches a pass across the middle and is immediately brought to a stop during a collision with a safety that lasts 0.6 seconds. What was the magnitude of force needed to stop the receiver

Explanation:

Given

Mass of receiver

Running at a speed of

time taken to stop

We know, impulse imparted is given by

Thus, 1200 N is needed to stop the receiver.

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.