-ww. A m = 15.0 kg
The block at Position A is released from the spring with 100 J of elastic potential energy. How
much kinetic energy does the block have at Position B? Explain how you know.

v = 3.65 m / s

Explanation:

In this exercise we use the conservation of mechanical energy

starting point. Point A compressed spring

          Em₀ = 100 J

final point. Point B uncompressed spring

         Em_f = K = ½ m v²

energy is conserved

         Em₀ = Em₀_f

         100 = ½ m v²

         v =

         v =

         v = 3.65 m / s

the answer would be a

1/0.14nm = 10^10/1.4 a lot