How far will a brick starting from rest fall freely in 3 seconds

When object falls freely we can say

its initial speed will be ZERO

and its acceleration due to gravity must be

a = g = 9.8 m/s^2a=g=9.8m/s2

Now we need to find the distance of free fall in 3 s of time

So here we will use kinematics

y = v* t + \frac{1}{2} at^2y=v∗t+21at2

now we will plug in all values in it

y = 0 + \frac{1}{2}* 9.8 * 3^2y=0+21∗9.8∗32

y = 44.1 my=44.1m

So it will fall by total distance of 44.1 m

answer: pseudoscience

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