39. A capacitor is formed from two concentric spherical conducting shells separated by vacuum. The inner sphere
has radius 12.5 cm, and the outer sphere has radius 14.8
cm. A potential difference of 120 V is applied to the
capacitor. (a) What is the energy density at r = 12.6 cm,
just outside the inner sphere? (b) What is the energy
density at r = 14.7 cm, just inside the outer sphere? (c) For
a parallel-plate capacitor the energy density is uniform in
the region between the plates, except near the edges of
the plates. Is this also true for a spherical capacitor?
40. Calculate the capacitance of a capacitor consisting of
two parallel plates separated by a layer of paraffin wax 0.5
thick, the area of each plate being 80 cm². The
dielectric constant constant for the wax is 2.0. If the
capacitor is connected to a 100 V source, calculate the
charge on the capacitor and the energy stored in the
capacitor
cm​

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).

it is the second option.

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.