two resistors of 4 ohms and 5 ohms in parallel ate connected to the terminal of a battery consisting of 4 dry cells each having an emf of 1.5 volts in series if the curreny in the 4 ohms resistor in 0.8 amperes find the current in the 5 ohms resistors and the internal resistance of the battery​

The magnets would be | n s | and | s n|

Ohm's law tells you that i = v/r where v is equivalent voltage and r is equivalent resistance of the circuit
since all circuits have the same voltage, your question is really asking which circuit has the lowest total resistance, since the lower the resistance, the higher the current
circuit a has a resistance of 5 ohms; circuit c is in series so has a resistance of 10 ohms; circuit b is in parallel and therefore has a resistance of 2.5 ohms (review your notes on adding resistances in parallel and series); therefore b has the highest current