A 5 kg box drops a distance of 10 m to the ground. If 70% of the initial potential energy goes into increasing the internal energy of the box, determine the magnitude of the increase.

Explanation:

From the given information:

The initial PE = m×g×h

= 5 kg × 9.81 m/s² × 10 m

= 490.5 J

The change in Potential energy P.E of the box is:

ΔP.E =

ΔP.E = 0 -

ΔP.E =

If we take a look at conservation of total energy for determining the change in the internal energy of the box;

this can be re-written as:

Here, K.E = 0

Also, 70% goes into raising the internal energy for the box;

Thus,

ΔU = 343.35  J

Thus, the magnitude of the increase is = 343.35 J

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is