A spring of spring constant k=8.25N/m is displaced from equilibrium by a distance of 0.150m. What is the stored energy in the form of spring potential energy? Show your work.

0.0928J

Explanation:

the pulling force of spring F=-kx

where x is the displacement from equilibrium position.

energy stored:

*** Its fine if you know nothing about calculus. Just apply the equation

  where U is the potential energy of the spring***

  put x=0.150, × = 0.0928J (corr. to 3 sig. fig.)

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