A person standing on Earth drops a ball. At the same time, a person standing at the bottom of a spaceship accelerating at 9.8 m/s2, in the absence of any significant fields in deep space, drops a ball. What would these people observe? Please help!

This did i unseated, sorry

Ireally just need to get finished with precal! i’m really sorry i have to do this! hope this !

Sorry i don’t know what to do

Initial velocity,  u = 4.9 m/sfinal velocity = v m/sinitial height,  h₁ =  245 m    final height, h₂ = 0a = -9.8  m/s²time taken = t secondss = ut + 0.5at²⇒  (h₂-h₁) = ut + 0.5at²⇒  0-245 = 4.9t + 0.5×(-9.8)×t²⇒ -245 = 4.9t - 4.9t²⇒ 4.9t² -4.9t -245 =0solving it, we get   t = 7.59sv  = u +  at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/svelocity is  69.48 m/s downward