A ball is thrown straight up with a speed of 30 m/s, and air resistance is negligible. How long does it take the ball to reach the maximum height?

3 seconds

Explanation:

Applying,

Applying,

v = u±gt Equation 1

Where v = final velocity, u = initial velocity, t = time, g = acceleration due to gravity.

From the question,

Given: v = 0 m/s ( at the maximum height), u = 30 m/s

Constant: g = -10 m/s

Substitute these values into equation 1

0 = 30-10t

10t = 30

t = 30/10

t = 3 seconds

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explanation: