Austin kicks a soccer ball with an initial velocity of 18.0 m/s at an angle of 35.0°. What are the horizontal and vertical components of the initial velocity?

Vx = 14.74 m/s.

Vy = 10.32 m/s

Explanation:

Applying,

Vx = Vcos∅ Equation 1

Where Vx = Horizontal component of the initial velocity, V = Intial Velocity, ∅ = Angle to the horizontal

From the question,

GIven: V = 18.0 m/s, ∅ = 35.0°

Substitute into equation 1

Vx = 18(cos35.0°)

Vx = 18(0.819)

Vx = 14.74 m/s.

Also for vertical component,

Vy = Vsin∅ Equation 2

Where Vy = vertical component of the initial velocity

Substituting the values above into equation 2

Therefore,

Vy = 18(sin35°)

Vy = 10.32 m/s