Volume of CO2 at STP of 27.0 g​

The volume of CO₂ at STP is equal to 13.73 L.

Explanation:

Given mass, m = 27 g

The molar mass of CO₂ = 44 g/mol

Let n is the number of moles. So,

n = given mass/molar mass

Let V is the volume of CO₂. So,

V = n×V'

Where

V' is the molar volume = 22.4 L

So,

V = 0.613 × 22.4

V = 13.73 L

Hence, the volume of CO₂ at STP is equal to 13.73 L.

explanation: magnetic pole, region at each end of a magnet where the external magnetic field is strongest. the south-seeking pole, or any pole similar to it, is called a south magnetic pole. unlike poles of different magnets attract each other; like poles repel each other.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂